Simetria central
Author: Pep Bujosa

Resposta

Triangles

Quadrilàters

A = (-1, 3)
B = (-3, 1)
C = (-1, -2)
poly1, c, a, b = Polygon(A, B, C)
Centre = (1, 2)
A' = Mirror(A, Centre)
B' = Mirror(B, Centre)
C' = Mirror(C, Centre)
poly1', c', a', b' = Polygon(A', B', C')
d = Segment(A, A')
e = Segment(B, B')
f = Segment(C, C')
g = false
h = false
i = false
D = (0, -1)
poly2, a_1, b_1, c_1, d_1 = Polygon(A, B, C, D)
A'_1 = Mirror(A, Centre)
B'_1 = Mirror(B, Centre)
C'_1 = Mirror(C, Centre)
D' = Mirror(D, Centre)
poly2', a'_1, b'_1, c'_1, d' = Polygon(A'_1, B'_1, C'_1, D')
j = Segment(D, D')