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Calculeu els següents límits, poso entre parčntesis el resultat perquč comprobeu si us surt bé: 1-`lim (sqrt(n+3))/(3n+7)=(0)` 2-`lim(sqrt(2n^2+3n-1))/(5n+1)=(sqrt(2)/5)` 3-`lim(2n^2+1)/sqrt(n-2)=(+\infty)` 4-`lim(n^2+2n-3)/sqrt(4n^4-3n^3+n-1)=(1/2)` 5-`lim (sqrt(9n^2+3n-7))/sqrt(4n^2-n+2)=(3/2)` 6-`lim(sqrt((n+1)·(n+2))-n)=(3/2)` 7-`lim(sqrt(n+1)-sqrt(n))=(0)` 8-`lim(sqrt(3n^2+4n+7)-sqrt(3n^2-5n+2))=(9/(2sqrt(3)))` |