Let AAcBcB, BBaCaC, CCbAbA be the Vecten squares. The lines BcBa, CaCb, AbAc bound a triangle A'B'C'. Let Oa, Ob, Oc be the circumcenters of BaCaA', CbAbB', AcBcC'. Then A'B'C' and OaObOc are homothetic with center Y the symmedian of A'B'C', lying in the Euler line of ABC.