Let P be a point in the Kiepert hyperbola. The cevians of P cut the perpendicular bisectors of ABC at Pa, Pb, Pc. The circles with centers Pa, Pb, Pc going through A, B, C have their radical center X in the Wallace hyperbola, and the circles {PaBC}, {PbCA}, {PcAB} have their radical center Y in the Kiepert hyperbola.