¿How can we obtain the argument of from m and the argument of? We remember that we define like a vector that it has: 1) Direction : The same one that if m is positive                         Opposite to the from if m is negative 2) Module: the module ofmultiplied by the absolute value of m Keep the same direction, positive m case, is equivalent to keep the argument, and change the direction by his opposite, negative m case, is equivalent to add 180 º to the argument. In consequence and summarizing, we can write:

INTERACTIVE ACTIVITY 1) You situate C point so that= 2. ¿Which relation is there between the arguments of and ? 2) You situate C point so that= 3. ¿ Which relation is there between the arguments of and ? 3) You situate C point so that = - 2. ¿ Which relation is there between the arguments of and ? 4) Finally, situate C point so that = - 0.75. ¿ Which relation is there between the arguments of and ? SOLUTION

a) The vectorhas argument 60º. Which argument have the following vectors :  3, - 2, ½, - 1.5 and  2.4?

b) If the vector has argument 145º . Which argument have vectors  - 5 , 4,  - 3,  2  and  -?

END OF ACTIVITY 3.5 ARGUMENT OF THE PRODUCT OF A SCALAR BY A VECTOR

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