ACTIVITY 5.8
PROJECTION OF A VECTOR ONTO ANOTHER

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We remember that geometrically, the scalar product of two vectors is the product of the module of one of them by the projection of the other onto him (projection with sign , that is to say, negative if his directions is opposite to the first vector):
                                                                   ·= |||a

In the other side, we can calculate the scalar product from the components:
                                                 ·= (a1,a2)·(b1,b2) = a1b1+ a2b2

Making equal, we get                    |||a = a1b1+ a2b2

where we can isolate the projection of onto :  
In a similar way we would get the projection of onto


INTERACTIVE ACTIVITY

Calculate next projections (with sign and perpendicular) and check the result in the applet of the right side:

1) Of vector (1,5) onto vector (4,1)

2) Of vector (4,1) onto vector (1,5)

3) Of vector (-3,1) onto vector (2,2)

4) Of vector (2,2) onto vector (-3,1)

5) Of vector (1,2) on vector (4,-2)

6) Of vector (2,1) onto vector (4,2)

7) Of vector (-4,-2) onto vector (2,1)

SOLUTION


HOMEWORK
We have seen that gives the projection (with sign) of onto. If we want the projection vector of ont, we have to multiply the previous projection by a unit vector that it has the direction of the vector. Like this vector is  , activity 3.7, vector projection of ontogoes by :
                                
Apply this procedure to calculate the vector projection of ontoin the three next cases:

a) = (1,5)  and= (4,1)
b) = (-3,1)  and= (2,2)
c) = (2,1)  and= (4,2)

END OF ACTIVITY 5.8
PROJECTION OF A VECTOR ONTO ANOTHER

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